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2011GRE考试选择题精炼(1)

发布时间:2016-03-02  编辑:查字典英语网小编

  2014gre数学选择题精炼

  Petworld has exactly fourteen animals that are kept in four separate cages according to the following conditions:

  Each cage contains exactly two, four, or six animals. Any cage containing a gerbil also contains at least one hamster; any cage containing a hamster also contains at least one gerbil. Any cage containing a lizard also contains at least one snake; any cage containing a snake also contains at least one lizard. Neither cage Y nor cage Z contains a gerbil. Neither cage W nor cage X contains a lizard.

  . Which one of the following could be a complete and accurate list of the animals kept in cages W and Y?

   W: one gerbil and one hamster; Y: two lizards and two snakes

   W: one gerbil and two hamsters; Y: one lizard and three snakes

   W: two gerbils and two hamsters; Y: one lizard and four snakes

   W: two gerbils and two hamsters; Y: three lizards and one snake

   W: two gerbils and two lizards; Y: two hamsters and two snakes

  . If there are exactly two hamsters in cage W and the number of gerbils in cage X is equal to the number of snakes in cage Y, then the number of snakes in cage Z must be exactly

   one

   two

   three

   four

   five

  . If cage Z contains exactly twice as many lizards as cage Y, which one of the following can be true?

   cage Y contains exactly two lizards.

   Cage Y contains exactly two snakes.

   Cage Y contains exactly four animals.

   Cage Z contains exactly three snakes.

   Cage Z contains exactly two animals.

  . If the number of animals in cage W is equal to the number of animals in cage Z, then which one of the following can be true?

   Cage W contains exactly six animals.

   Cage X contains exactly six animals.

   Cage Y contains exactly one snake.

   Cage Y contains exactly three snakes.

   Cage Z contains exactly four snakes.

  . If cage W contains six animals, which one of the following must be true?

   Cage W contains two gerbils.

   Cage X contains four animals.

   Cage Z contains two snakes.

   The number of snakes in cage Y is equal to the number of lizards in cage Y.

   The number of snakes in cage Z is equal to the number of lizards in cage Z.

  . At most, how many snakes can occupy cage Y at any one time?

   one

   two

   three

   four

   five

  KEYS: ADCDED

  

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