下面GMAT思为大家整理了GMAT数学例题详解,供考生们参考,以下是详细内容。
1、一个班总共有60个字生,他们要么学习西班牙语,要么学法语,或两者都学。学西班牙语的有36人,其中包括6个学两种语言的。问学法语的有多少人?
【答案】:30
【思路】
根据集合定律:AUB=A+B-AB交集,设学法语的为X人---60=X+36-6--X=60-36+6=30
2、一个单位给员工做胸牌,胸牌号码由2-9中的3位数组成,不重复。已经做了330个,问还可做多少个?
【答案】6
【思路】
2-9一共是8个数字,从中取出三个数字不重复的做法一共有:P8,3=336
已经做了330,则还要作336-330=6.
3、直线X+2Y=6与X轴和Y轴相交而成的三角形的面积。
【答案】9
【思路】
先求出直线与X轴和Y轴的交点:令Y=0--X=6---X轴交点
令X=0--Y=3--Y轴交点
面积S=1/236=9
4、从0-9这十个数中由四位数组成电话号码,首位不为零。问:能组成多少个电话号码?
【答案】9000
【思路一】
由0~9组成的首位不为0的四位数为1000~9999,所以总数为10000-1000=9000
【思路二】
先在九个中(除0)找一个给第一位,即为C9,1
然后后面每个都有十种选择10^3
所以910^3=9000
5、一个圆上的7个点,能组成的三角形的数目与能组成的四边形的数目之比。
【答案】1
【思路】
每三个点组成一个三角形,因此三角形的数目为C7,3
每四个点组成一个四边形,因此四边形的数目为C7,4
C7,3/C7,4=1
以上就是GMAT数学例题详解的详细内容,考生可针对文中介绍的方法进行有针对性的备考。最后预祝大家在GMAT考试中取得好成绩!
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