1、To find the median of data given by percentage给了不同年龄range, 和各个range的percentage, 问median 落在哪个range里. 把percentage加到50%就是median的range了.担小心一点,range首先要保证是有序排列.
Example for this:
Given: 10~20 = 20%, 30~50 = 30%, 0~10 = 40%, 20~30 = 10%, 问median在哪个range里.
分析: 千万不要上来就加,要先排序,切记!重新排序为: 0~10 = 40%, 10~20 = 20%, 20~30 = 10%, 30~50 = 40%. 然后从小开始加, median落在 10~20这个range里.
如果觉得比较玄乎,我的方法,GRE大部分的题都可以这么搞。0~10岁 40匹ETS猪,10~20岁 20匹ETS猪,20~30岁匹ETS猪,30~50岁 匹ETS猪,这100匹ETS猪按着年龄排下来,你说第五十匹ETS猪的年龄落在那个范围。
2、比较,当n1时,n,1,2 和1,2,3的标准方差谁大standard error 和 standard variation 都是用来衡量一组数据的离散程度的统计数值,只不过由于standard error中涉及绝对值,在数学上是很难处里的所以,都用标准方差,实际上standard error更合理一些,它代表了数据和平均值的平均距离.很明显题目中如果n=0的话,0,1,2的离散程度应该和1,2,3的离散程度相同.如果 n0,则n,1,2,的离散程度大于后者,而0Key: n是整数, 前〉=后,2,3,4,5
1,2,3,4,5
1,2,3,4,5
其中括号里的是出现的频率,问MEAN和AVERAGE相等的有那些.
答案:只有第二个.
mean-arithmetic mean 算术平均值/ 5 = 3
average-weighted average 加权平均值: /=48/16=3
4、正态分布题
一列数从0到28,给出正态分布曲线.75%的percentile是20,85%的percentile是r,95%的percentile是26,问r与23的大小.
Key:r23下面是来自柳大侠的七种武器中的正态分布
5、正态分布
高斯分布的概率密度函数为一钟型曲线,即a为均值, 为标准方差,曲线关于x=a的虚线对称, 决定了曲线的胖瘦.
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